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4.9x^2+6x+0.6=0
a = 4.9; b = 6; c = +0.6;
Δ = b2-4ac
Δ = 62-4·4.9·0.6
Δ = 24.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{24.24}}{2*4.9}=\frac{-6-\sqrt{24.24}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{24.24}}{2*4.9}=\frac{-6+\sqrt{24.24}}{9.8} $
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